Max Velocity Question

[SALSAA]

So, I was pushing for a bonus record (skilled, ikr) and I got a really good pipetrick. With /speedo, the speed showed 3,600 u/s. Is this even possible? Was it a speedo error? Oh, and also I was moving half diagonally.
Would appreciate an answer soon, especially by RNC (that guy knows his stuff)

[RNC1839]

The reason is that the cl_showpos velocity is actually just all 3 speeds merged into one. Guyyst sent me the actual math behind it and I think it was like the square root of all 3 velocities added together.

especially by RNC (that guy knows his stuff)

[guyyst]

Uhm he specifically said that he used !speedo, not cl_showpos.
But what RNC said still holds up, since !speedo is calculated like this: sqrt(x_vel^2 + y_vel^2)

So you probably had full speed on one axis and a little speed on the other, since the max velocity is 3500 per axis.

[SALSAA]

Uhm he specifically said that he used !speedo, not cl_showpos.
But what RNC said still holds up, since !speedo is calculated like this: sqrt(x_vel^2 + y_vel^2)

So you probably had full speed on one axis and a little speed on the other, since the max velocity is 3500 per axis.

Thanks. That was what I was guessing. Also I think its sqrt(x_vel^2 + z_vel^2) because vertical velocity isn't accounted for in /speedo. Emi was arguing against for like 15 minutes a couple weeks ago >:l

[guyyst]

Uhm he specifically said that he used !speedo, not cl_showpos.
But what RNC said still holds up, since !speedo is calculated like this: sqrt(x_vel^2 + y_vel^2)

So you probably had full speed on one axis and a little speed on the other, since the max velocity is 3500 per axis.

Thanks. That was what I was guessing. Also I think its sqrt(x_vel^2 + z_vel^2) because vertical velocity isn't accounted for in /speedo. Emi was arguing against for like 15 minutes a couple weeks ago >:l

Oh I just forgot which axis was the vertical one right there